RD Sharma Class 9 Solutions Chapter 24 Exercise 24.2 (Updated 2021-22)

RD Sharma Class 9 Solutions Chapter 24 Exercise 24.2

RD Sharma Class 9 Solutions Chapter 24 Exercise 24.2: You can get the PDF for RD Sharma Class 9 Solutions Maths Chapter 24 Exercise 24.2 for free. This PDF is created by our experts team to provide students the detailed solutions. These solutions will be very beneficial for you Class 9 exams. 

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Access RD Sharma Class 9 Solutions Maths Chapter 24 Exercise 24.2

Question 1: Calculate the mean for the following distribution:

image 1

Solution:

image 2

Formula to calculate mean:

image 3

= 281/40

= 7.025

⇒ Mean for the given distribution is 7.025.

Question 2: Find the mean of the following data:

image 4

Solution:

image 5

Formula to calculate mean:

image 3

= 2650/106

= 25

⇒ Mean for the given data is 25.

Question 3: The mean of the following data is 20.6 .Find the value of p.

image 7 1

Solution:

image 8

Formula to calculate mean:

image 3

= (25p + 530)/50

Mean = 20.6 (Given)

So,

20.6 = (25p + 530)/50

25p + 530 = 1030

25p = 1030 − 530 = 500

or p = 20

⇒ The value of p is 20.

Question 4: If the mean of the following data is 15, find p.

q 4 1

Solution:

q 4 2

Formula to calculate mean:

image 3

= (10p + 445)/(p + 27)

Mean = 15 (Given)

So, (10p + 445)/(p + 27) = 15

10p + 445 = 15(p + 27)

10p – 15p = 405 – 445 = -40

-5p = -40

or p = 8

⇒ The value of p is 8.

Question 5: Find the value of p for the following distribution whose mean is 16.6.

q5 1

Solution:

q 5 2

Formula to calculate mean:

image 3

= (24p + 1228)/100

Mean = 16.6 (given)

So, (24p + 1228)/100 = 16.6

24p + 1228 = 1660

24p = 1660 – 1228 = 432

p = 432/24 = 18

⇒ The value of p is 18.

Question 6: Find the missing value of p for the following distribution whose mean is 12.58.

q6 1

Solution:

q6 2

Formula to calculate mean:

image 3

= (7p + 524)/50

Mean = 12.58 (given)

So, (7p + 524)/50 = 12.58

7p + 524 = 12.58 x 50

7p + 524 = 629

7p = 629 – 524 = 105

p = 105/7 = 15

⇒ The value of p is 15.

Question 7: Find the missing frequency (p) for the following distribution whose mean is 7.68.

q7 1

Solution:

q7 2

Formula to calculate mean:

image 3

= (9p + 303)/(p+41)

Mean = 7.68 (given)

So, (9p + 303)/(p+41) = 7.68

9p + 303 = 7.68 (p + 41)

9p + 303 = 7.68p + 314.88

9p − 7.68p = 314.88 − 303

1.32p = 11.88

or p = (11.881)/(1.32) = 9

⇒ The value of p is 9.

We have included all the information regarding CBSE RD Sharma Class 9 Solutions Chapter 24 Exercise 24.2. If you have any query feel free to ask in the comment section. 

FAQ: RD Sharma Class 9 Solutions Chapter 24 Exercise 24.2

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