RD Sharma Class 9 Solutions Chapter 10 VSAQs (Updated for 2021-22)

RD Sharma Class 9 Solutions Chapter 10 VSAQs

RD Sharma Class 9 Solutions Chapter 10 VSAQs: All your Maths ssignments and class tests can be done easily when you are studying RD Sharma Solutions Class 9 Maths. You can find easy to understand solutions designed by subject matter experts. To know more about the RD Sharma Class 9 Solutions Chapter 10 VSAQs, read the whole blog. 

Access answers of RD Sharma Class 9 Solutions Chapter 10 VSAQs

Question 1.
Define complementary angles.
Solution:
Two angles whose sum is 90°, are called complementary angles.

Question 2.
Define supplementary angles.
Solution:
Two angles whose sum is 180°, are called supplementary angles.

Question 3.
Define adjacent angles.
Solution:
Two angles which have common vertex and one arm common are called adjacent angles.

Question 4.
The complement of an acute angles is…….
Solution:
The complement of an acute angles is an acute angle.

Question 5.
The supplement of an acute angles is………
Solution:
The supplement of an acute angles is a obtuse angle.

Question 6.
The supplement of a right angle is…….
Solution:
The supplement of a right angle is a right angle.

Question 7.
Write the complement of an angle of measure x°.
Solution:
The complement of x° is (90° – x)°

Question 8.
Write the supplement of an angle of measure 2y°.
Solution:
The supplement of 2y° is (180° – 2y)°

Question 9.
If a wheel has six spokes equally spaced, then find the measure of the angle between two adjacent spokes.
Solution:
Total measure of angle around a point = 360°
Number of spokes = 6
∴ Angle between the two adjacent spokes = \(\frac { { 360 }^{ \circ } }{ 6 }\) = 60°

Question 10.
An angle is equal to its supplement. Determine its measure.
Solution:
Let required angle = x°
Then its supplement angle = 180° – x
x = 180° – x
⇒ x + x = 180°
⇒  2x = 180° ⇒  x = \(\frac { { 180 }^{ \circ } }{ 2 }\) = 90°
∴ Required angle = 90°

Question 11.
An angle is equal to five times its complement. Determine its measure.
Solution:
Let required measure of angle = x°
∴  Its complement angle = 90° – x
∴  x = 5(90° – x)
⇒  x = 450° – 5x
⇒  x + 5x = 450°
⇒  6x = 450°
⇒ x = \(\frac { { 450 }^{ \circ } }{ 6 }\) = 75°
∴ Required angle = 75°

Question 12.
How many pairs of adjacent angles are formed when two lines intersect in a point?
Solution:
If two lines AB and CD intersect at a point O, then pairs of two adjacent angles are, ∠AOC and ∠COB, ∠COB and ∠BOD, ∠BOD and DOA, ∠DOA and ∠ZAOC
i.e, 4 pairs
RD Sharma Mathematics Class 9 Solutions Chapter 10 Congruent Triangles VSAQS

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FAQs on RD Sharma Class 9 Solutions Chapter 10 VSAQs

How many questions are there in RD Sharma Class 9 Solutions Chapter 10 VSAQs?

There are 12 questions in RD Sharma Class 9 Solutions for Chapter 10 VSAQs.

Is it even beneficial to study RD Sharma for Class 9 Solutions Chapter 10 VSAQs?

Yes, your preparation will be strengthened with this amazing help book. All your questions will be answered by this book.

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The solutions are relevant as they are designed by the subject matter experts.  

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