RD Sharma Class 9 Solutions Chapter 15 Exercise 15.3 (Updated 2021-22)

RD Sharma Class 9 Solutions Chapter 15 Exercise 15.3: Our experts created this PDF in a simple way. By preparing for the exams, you can easily understand these 9 class solutions from RD Sharma Chapter 15 Exercise 15.3 Solutions.

• RD Sharma Class 9 Maths Solutions

Download RD Sharma Class 9 Solutions Chapter 15 Exercise 15.3

RD Sharma Class 9 Solutions Chapter 15 Exercise 15.3

Access RD Sharma Class 9 Solutions Chapter 15 Exercise 15.3

Question 1.
Three girls Ishita, Isha and Nisha are playing a game by standing on a circle of radius 20 m drawn in a park. Ishita throws a ball to Isha, Isha to Nisha and Nisha to Ishita. If the distance between Ishita and Isha and between Isha and Nisha is 24 m each, what is the distance between Ishita and Nisha. [NCERT]
Solution:
∵ Distance between Isha and Ishita and Ishita and Nisha is same
∴ RS = SM = 24 m
∴They are equidistant from the centre
In right ∆ORL,
OL² = OR² – RL²


Hence distance between Ishita and Nisha = 38.4 m

Question 2.
A circular park of radius 40 m is situated in a colony. Three beys Ankur, Amit and Anand are sitting at equal distance on its boundary each having a toy telephone in his hands to talk to each other. Find thelength of the string of each phone. [NCERT]
Solution:
Radius of circular park = 40 m
Ankur, Amit and Anand are sitting at equal distance to each other By joining them, an equilateral triangle ABC is formed produce BO to L which is perpendicular bisector of AC

∴ BL = 40 + 20 = 60 m (∵ O is centroid of ∆ABC also)
Let a be the side of ∆ABC

Hence the distance between each other = 403–√ mRD Sharma Mathematics Class 9 Solutions Chapter 15 Areas of Parallelograms and Triangles

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