RD Sharma Class 11 Solutions Chapter 23 Exercise 23.6 (Updated for 2021-22)

RD Sharma Solutions Class 11 Maths Chapter 23 Exercise 23.6: Students should practise the problems on a regular basis to improve their understanding of the concepts. RD Sharma Solutions Class 11 Maths Chapter 23 Exercise 23.6 pdf can be downloaded from the links provided below for a better understanding of the concepts.

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RD Sharma Solutions Class 11 Maths Chapter 23 Exercise 23.6

This exercise explains one of the several types of equations for a straight line, namely the intercept form of a line, using examples to help students understand the concepts. Students who are having difficulties in solving the exercise wise challenges can download a pdf of RD Sharma Class 11 Solutions prepared by Kopykitab’s subject experts.

Access answers to RD Sharma Solutions Class 11 Maths Chapter 23 Exercise 23.6- Important Question with Answers

1. Find the equation to the straight line
(i) cutting off intercepts 3 and 2 from the axes.

(ii) cutting off intercepts -5 and 6 from the axes.

Solution:

(i) Cutting off intercepts 3 and 2 from the axes.

Given:

a = 3, b = 2

Let us find the equation of line cutoff intercepts from the axes.

By using the formula,

The equation of the line is x/a + y/b = 1

x/3 + y/2 = 1

By taking LCM,

2x + 3y = 6

∴ The equation of line cut off intercepts 3 and 2 from the axes is 2x + 3y = 6

(ii) Cutting off intercepts -5 and 6 from the axes.

Given:

a = -5, b = 6

Let us find the equation of line cutoff intercepts from the axes.

By using the formula,

The equation of the line is x/a + y/b = 1

x/-5 + y/6 = 1

By taking LCM,

6x – 5y = -30

∴ The equation of line cut off intercepts 3 and 2 from the axes is 6x – 5y = -30

2. Find the equation of the straight line which passes through (1, -2) and cuts off equal intercepts on the axes.

Solution:

Given:

A line passing through (1, -2)

Let us assume, the equation of the line cutting equal intercepts at coordinates of length ‘a’ is

By using the formula,

The equation of the line is x/a + y/b = 1

x/a + y/a = 1

x + y = a

The line x + y = a passes through (1, -2)

Hence, the point satisfies the equation.

1 -2 = a

a = -1

∴ The equation of the line is x+ y = -1

3. Find the equation to the straight line which passes through the point (5, 6) and has intercepts on the axes
(i) Equal in magnitude and both positive

(ii) Equal in magnitude but opposite in sign

Solution:

(i) Equal in magnitude and both positive

Given:

a = b

Let us find the equation of line cutoff intercepts from the axes.

By using the formula,

The equation of the line is x/a + y/b = 1

x/a + y/a = 1

x + y = a

The line passes through the point (5, 6)

Hence, the equation satisfies the points.

5 + 6 = a

a = 11

∴ The equation of the line is x + y = 11

(ii) Equal in magnitude but opposite in sign

Given:

b = -a

Let us find the equation of line cutoff intercepts from the axes.

By using the formula,

The equation of the line is x/a + y/b = 1

x/a + y/-a = 1

x – y = a

The line passes through the point (5, 6)

Hence, the equation satisfies the points.

5 – 6 = a

a = -1

∴ The equation of the line is x – y = -1

4. For what values of a and b the intercepts cut off on the coordinate axes by the line ax + by + 8 = 0 are equal in length but opposite in signs to those cut off by the line 2x – 3y + 6 = 0 on the axes.

Solution:

Straight Lines Ex 23.6 Q5

Straight Lines Ex 23.6 Q6

Straight Lines Ex 23.6 Q7

Straight Lines Ex 23.6 Q8

Straight Lines Ex 23.6 Q9

Straight Lines Ex 23.6 Q10

Straight Lines Ex 23.6 Q11

Straight Lines Ex 23.6 Q12

Straight Lines Ex 23.6 Q13

Straight Lines Ex 23.6 Q14

Straight Lines Ex 23.6 Q15

Straight Lines Ex 23.6 Q16

Straight Lines Ex 23.6 Q17

Straight Lines Ex 23.6 Q18

Straight Lines Ex 23.6 Q19

We have provided complete details of RD Sharma Solutions Class 11 Maths Chapter 23 Exercise 23.6. If you have any queries related to CBSE Class 11, feel free to ask us in the comment section below.

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