RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2 2022

RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2: In this exercise, we’ll look at the mean deviation of a discrete frequency distribution and how to compute it using an algorithm. Students who are experiencing difficulty solving arithmetic questions can use the solutions prepared by experts, who have presented the solutions in the most straightforward manner possible for any pupil to understand. Students who are unable to resolve their doubts during class can refer the RD Sharma Class 11 Maths Solutions. Students can easily obtain the RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2 pdf by clicking on the links below.

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Download RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2 Free PDF

RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2

Access answers to RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2- Important Question with Answers

1. Calculate the mean deviation from the median of the following frequency distribution:

Heights in inches	58	59	60	61	62	63	64	65	66
No. of students	15	20	32	35	35	22	20	10	8

Solution:

To find the mean deviation from the median, firstly let us calculate the median.

We know, Median is the Middle term,

So, Median = 61

Let x_i =Heights in inches

And, f_i = Number of students

x_i	f_i	Cumulative Frequency	\|d_i\| = \|x_i – M\| = \|x_i – 61\|	f_i \|d_i\|
58	15	15	3	45
59	20	35	2	40
60	32	67	1	32
61	35	102	0	0
62	35	137	1	35
63	22	159	2	44
64	20	179	3	60
65	10	189	4	40
66	8	197	5	40
N = 197	Total = 336

N=197

\(MD = \frac{1}{n}\sum_{i=1}^{n}|d_{i}|\)

= 1/197 × 336

= 1.70

∴ The mean deviation is 1.70.

2. The number of telephone calls received at an exchange in 245 successive on2-minute intervals is shown in the following frequency distribution:

Number of calls	0	1	2	3	4	5	6	7
Frequency	14	21	25	43	51	40	39	12

Compute the mean deviation about the median.

Solution:

To find the mean deviation from the median, firstly let us calculate the median.

We know, Median is the even term, 3+5/2 = 4

So, Median = 8

Let x_i =Number of calls

And, f_i = Frequency

x_i	f_i	Cumulative Frequency	\|d_i\| = \|x_i – M\| = \|x_i – 61\|	f_i \|d_i\|
0	14	14	4	56
1	21	35	3	63
2	25	60	2	50
3	43	103	1	43
4	51	154	0	0
5	40	194	1	40
6	39	233	2	78
7	12	245	3	36
Total = 366
Total = 245

N = 245

\(MD = \frac{1}{n}\sum_{i=1}^{n}|d_{i}|\)

= 1/245 × 336

= 1.49

∴ The mean deviation is 1.49.

Statistics Ex 32.2 Q3

Statistics Ex 32.2 Q4(i)

Statistics Ex 32.2 Q4(ii)

Statistics Ex 32.2 Q4(iii)

Statistics Ex 32.2 Q4(iv)

Statistics Ex 32.2 Q5

We have provided complete details of RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2. If you have any queries related to CBSE Class 11, feel free to ask us in the comment section below.

FAQs on RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2

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There are a total of 5 questions in RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2.

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RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2 (Updated for 2021-22)