RD Sharma Solutions Class 12 Maths Chapter 2 Exercise 2.5

RD Sharma Solutions Class 12 Maths Chapter 2 Exercise 2.5: RD Sharma Solutions for Class 12, Maths Chapter 2, helps students who wish to achieve a good academic score in the exam. Solutions are expertly designed to increase students’ confidence to understand the concepts covered in this chapter and how to solve problems in a short period of time.

Our experts prepare these materials based on the Class 12 CBSE syllabus, keeping in mind the types of questions asked in the RD Sharma solution. Chapter 2 Functions explains the function and domains of functions and functions. It has four practices. Students can easily get answers to problems in RD Sharma Solutions for Class 12.

Download RD Sharma Solutions Class 12 Maths Chapter 2 Exercise 2.5 PDF:

 


 

RD Sharma Solutions Class 12 Maths Chapter 2 Exercise 2.5: Important Topics From The Chapter

Let us have a look at some of the important concepts that are discussed in this chapter.

  • Classification of functions
    • Types of functions
      • Constant function
      • Identity function
      • Modulus function
      • Integer function
      • Exponential function
      • Logarithmic function
      • Reciprocal function
      • Square root function
    • Operations on real functions
    • Kinds of functions
      • One-one function
      • On-to function
      • Many one function
      • In to function
      • Bijection
    • Composition of functions
    • Properties of the composition of functions
    • Composition of real function
    • Inverse of a function
    • Inverse of an element
    • Relation between graphs of a function and its inverse

Important Questions from RD Sharma Solutions Class 12 Maths Chapter 2 Exercise 2.5

Question :

Consider  given by . Show that  is invertible. Find the inverse .

Answer :

 test of 

Let  and  be two elements of domain  such that
  
  
  
   is one-one.
 
 test for 
Let  be in the co-domain , such that 
  
  
   (Domain)
   is onto.
So,  is a bijection and hence, it is invertible.
 
Now we have to find 
Let               —- ( 1 )
  
  
  
  
From ( 1 ),
So,     
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