RS Aggarwal Class 7 Maths Chapter 1 Integers Exercise 1.3 Solutions (2021-22)

RS Aggarwal Solutions Class 7 Maths Chapter 1 Exercise 1.3: The third Exercise of RS Aggarwal Textbook i.e., Exercise 1.3 of Chapter 1 for Math Class 7 has got the set of only three questions in totality. These 3 questions thorough need to be solved using the “Division of Integers” method. We will share how to do it with every single step required to keep in mind below such that you understand the basics and perform well in your Class 7 final exams. Meanwhile, download the free PDF of RS Aggarwal Solutions Class 7 Maths Chapter 1 Exercise 1.3.

• RS Aggarwal Solutions Class 7 Maths Chapter 1

Download RS Aggarwal Solutions Class 7 Maths Chapter 1 Exercise 1.3 Free PDF

RS Aggarwal Solutions Class 7 Maths Chapter 1 Exercise 1.3

Access RS Aggarwal Solutions Class 7 Maths Chapter 1 Exercise 1.3

Question 1.
Solution:
(i) 65 by -13 = 65 ÷ (-13) = -5
(ii) -84 by 12 = -84 ÷ 12 = -7
(iii) -76 by 19 = -76 ÷ 19 = -4
(iv) -132 by 12 = -132 ÷ 12 = -11
(v) -150 by 25 = -150 ÷ 25 = -6
(vi) -72 by -18= -72 ÷ (-18)
(vii) -105 by -21 = -105 ÷ (-21) = 5
(viii) -36 by -1 = -36 ÷ (-1) = 36
(ix) 0 by -31 = 0 ÷ (-31) = 0
(x) -63 by 63 = -63 ÷ 63 = -1
(xi) -23 by -23 = -23 ÷ (-23)
(xii) -8 by 1 = -8 ÷ 1 = -8

Question 2.
Solution:
(i) 72 ÷ (………) = -4
⇒ 72 ÷ (-4) = -18
72 + (-18) = -4
(ii) -36 ÷ (………) = -4
⇒ -36 ÷ (-4) = 9
-36 ÷ (9) = -4
(iii) (………) ÷ (-4) = 24
⇒ -4 x 24 = -96
(-96) ÷ (-4) = 24
(iv) (……….) ÷ 25 = 0
(…….) ÷ 25 = 0 {0 ÷ a = 0}
(v) (………) ÷ (-1) = 36
⇒ 36 x (-1) = -36
(-36) ÷ (-1) = 36
(vi) (………..) + 1 = 37
⇒ (-37) x 1 = -37
(-37) ÷ 1 = -37
(vii) 39 ÷ (……….) = -1
⇒ 39 ÷ (-1) = -39
39 ÷ (-39) = -1
(viii) 1 ÷ (………) = -1
⇒ -1 ÷ 1 = -1
1 ÷ (-1) = -1
(ix) -1 + (………) = -1
-1 ÷ (1) = -1

Question 3.
Solution:
(i) True : as zero divided by non zero integer is zero.
(ii) False : as division by zero is not meaning full
(iii) False : as (-5) ÷ (-1) = 5 (product will be positive)
(iv) True : as -a ÷ 1 = -a
(v) False : as (-1) ÷ (-1) = 1
(vi) True.

What is the “Division of integers”?

To understand the “Division of integers” in a simple manner, it can be defined as the operation which is the reverse of “Multiplication of integers”. It is a method to make evident that for how many times a certain number is stored in another number. There is only one difference here, that in the “Division of integers”, there is no surety that the quotient will be an integer always.

For Example.,

In the question, 88 ÷ 11 = 8

Here, if you want to know that how many times 11 is stored in 88, then the answer will be 8 times.

Continue grasping the techniques we have mentioned in this article to understand the rules on “Division of integers”.

Please take note of the following things:

• Quotient × Divisor = Dividend
• Dividend ÷ Divisor = Quotient
• Dividend ÷ Quotient = Divisor

RS Aggarwal Solutions Class 7 Maths Chapter 1 Exercise 1.3, “Division of integers” – RULES

RULE 1: According to rule 1,

Positive ÷ Negative = Negative

It means that the division of the Numerator being positive and the denominator being negative leads to the negative result. So if the dividend is positive and the divisor is negative then the quotient ideally will be negative.

For Example.,

33 ÷ (-11) = -3

RULE 2: According to rule 2,

Positive ÷ Positive = Positive

It means that the division of the two positive integers is always positive in the result. So if the dividend and the divisor are positive then the quotient ideally will be positive.

For Example.,

33 ÷ 11 = 3

RULE 3: According to rule 3,

Negative ÷ Positive = Negative

It means that the division of the Numerator being negative and the denominator being positive leads to the negative result. So if the dividend is negative and the divisor is positive then the quotient ideally will be negative.

For Example.,

(-33) ÷ 11 = -3

RULE 4: According to rule 4, Negative ÷ Negative = Positive

It means that the division of two negative integers leads to a negative result. So if the dividend and the divisor both are negative then the quotient ideally will always be positive.

For Example.,

(-33) ÷ (-11) = 3

Hope all of our students in CBSE Class 7 are finding the Maths interesting now. Keep staying connected with us for more and more updates and simple tricks to solve multiple questions.

RS Aggarwal Class 7 Maths Chapter 1 Exercise 1.3 Solutions – FAQs